Question

(a+10) (a+2)>a (a+12)​

Answer 1

все расписано , на рисунке

Answer 2

Let's solve the inequality step by step:

(a + 10)(a + 2) > a(a + 12)

Expanding both sides:

a^2 + 2a + 10a + 20 > a^2 + 12a

Simplifying:

a^2 + 12a + 20 > a^2 + 12a

The quadratic terms (a^2) cancel out on both sides, and we are left with:

20 > 0

This inequality is true for all values of a. Therefore, the original inequality (a + 10)(a + 2) > a(a + 12) holds true for any real value of a.