Question

3^(2х)+3^(2х+1)-108=0​

Answer 1

Данный ответ представлен фотографией.

Answer 2

Ответ:

ддсддсдддсддчщщящсд

Answer 3

The equation you've provided is a quadratic equation in terms of $3^{2x}$. Let's solve it step by step:

The equation is: $3^{2x} + 3^{2x+1} - 108 = 0$.

First, notice that $3^{2x+1}$ can be written as $3 \cdot 3^{2x}$:

$3^{2x} + 3 \cdot 3^{2x} - 108 = 0$.

Now, factor out $3^{2x}$:

$3^{2x} (1 + 3) - 108 = 0$, $3^{2x} (4) - 108 = 0$, $4 \cdot 3^{2x} - 108 = 0$.

Now, we can isolate $3^{2x}$:

$4 \cdot 3^{2x} = 108$, $3^{2x} = \frac{108}{4}$, $3^{2x} = 27$, $3^{2x} = 3^3$.

Since the bases are the same (both are 3), we can equate the exponents:

$2x = 3$.

Now, solve for $x$:

$x = \frac{3}{2}$.

So, the solution for the equation $3^{2x} + 3^{2x+1} - 108 = 0$ is $x = \frac{3}{2}$.