Question

X³-x² если х=-2,х=0,1 решите пж​

Answer 1

Ответ:

${x}^{3} - {x}^{2} = {( - 2)}^{3} - {(0.1)}^{2} = - 8 - {( \frac{1}{10} )}^{2} = - 8 - \frac{1}{100} = \frac{ - 800 - 1}{100} = - \frac{801}{100} = - 8.01$

Answer 2

To solve the equation $x^3 - x^2$ for the given values of $x = -2$, $x = 0$, and $x = 1$, we substitute each value into the equation and evaluate the expression.

For $x = -2$: $(-2)^3 - (-2)^2 = -8 - 4 = -12$

For $x = 0$: $0^3 - 0^2 = 0 - 0 = 0$

For $x = 1$: $1^3 - 1^2 = 1 - 1 = 0$

Therefore, the solutions are: For $x = -2$, the value of the expression is -12. For $x = 0$, the value of the expression is 0. For $x = 1$, the value of the expression is 0.