Question

(X^2+2x-2)^2+x(x^2+2x-2)=2x^2

Answer 1

я написал решение на листочке ===>>

Answer 2

It seems like you've provided an equation:

$(x^2+2x-2)^2 + x(x^2+2x-2) = 2x^2$

To solve for $x$, we'll need to simplify the equation and then solve for $x$ using algebraic methods. Let's go through the steps:

Step 1: Expand the expressions on the left-hand side: $(x^2+2x-2)^2 + x(x^2+2x-2) = x^4 + 4x^3 - 2x^2 + 2x^3 + 4x^2 - 2x = x^4 + 6x^3 + 2x^2 - 2x$

Step 2: Combine like terms on the left-hand side: $x^4 + 6x^3 + 2x^2 - 2x = 2x^2$

Step 3: Move all terms to one side of the equation to set it equal to zero: $x^4 + 6x^3 - 2x^2 - 2x = 0$

Step 4: Factor out common terms if possible. In this case, there doesn't seem to be an obvious common factor.

Step 5: Since the equation is a quartic equation (fourth-degree polynomial), it might not have a simple algebraic solution. You might need to use numerical methods or a graphing calculator to find approximate solutions.

Without further constraints or information, it's challenging to provide an exact solution for $x$. If you're looking for a numerical approximation of solutions, you could use numerical methods like Newton's method or use graphing software to find the values of $x$ that satisfy the equation.