Question

1). 3у(4у-1) - 6у(1,5 + 2у) = 4,8.2) 0,2а(5а - 8) + 3,6 = а(а - 0,7).​

Answer 1

Ответ:

Вроде все получилось правильно

Answer 2

It looks like you've provided two equations with variables and constants. It seems you want to solve for the values of the variables "у" and "а" that satisfy these equations. Let's solve each equation step by step.

Equation 1: $3у(4у-1) - 6у(1.5 + 2у) = 4.8$

First, distribute the terms: $12у^2 - 3у - 9у - 12у^2 = 4.8$

Combine like terms: $-12у = 4.8$

Now, solve for "у": $у = \frac{4.8}{-12}$ $у = -0.4$

So, the solution for the first equation is $у = -0.4$.

Equation 2: $0.2а(5а - 8) + 3.6 = а(а - 0.7)$

Distribute the terms: $1а^2 - 0.7а + 3.6 = 1а^2 - 8а + 3.6$

Subtract $1а^2$ and $3.6$ from both sides: $-0.7а = -8а$

Divide both sides by $-0.7$ (which is the same as multiplying by $-1.42857$): $а = 8а \cdot 1.42857$ $а = 11.42856а$

Now, divide both sides by $11.42856$ to solve for "а": $а = \frac{а}{11.42856}$ $а ≈ 0.0879$

So, the solution for the second equation is $а ≈ 0.0879$.

To summarize:

• Solution for the first equation: $у = -0.4$
• Solution for the second equation: $а ≈ 0.0879$