Question

4x^2-52x+169<=0 ....

Answer 1

(2x-13)²=0

2x-13=0

2x=13

x=13/2

Answer 2

Ответ:

нет корней

Объяснение:

D=25-4×4×169=25-2705=-2679

Answer 3

To solve the inequality $4x^2 - 52x + 169 \leq 0$, you can start by factoring the quadratic expression and then finding the values of $x$ that satisfy the inequality.

First, let's factor the quadratic expression:

$4x^2 - 52x + 169 = (2x - 13)(2x - 13)$

Now, we have the quadratic expression factored as a perfect square:

$(2x - 13)^2 \leq 0$

To solve for $x$, take the square root of both sides:

$\sqrt{(2x - 13)^2} \leq \sqrt{0}$

$2x - 13 \leq 0$

Now, add 13 to both sides of the inequality:

$2x \leq 13$

Finally, divide by 2:

$x \leq \frac{13}{2}$

So, the solution to the inequality $4x^2 - 52x + 169 \leq 0$ is $x \leq \frac{13}{2}$.