Question

3) 2(3x+5)2 =7(3x+5);​

Answer 1

Ответ:

Я думаю так,фотка ниже

Answer 2

To solve the equation 2(3x+5)^2 = 7(3x+5), you can follow these steps:

1. Expand both sides of the equation:

   2(9x^2 + 30x + 25) = 7(3x+5)

   Now, distribute the constants 2 and 7 to the terms inside the parentheses:

   18x^2 + 60x + 50 = 21x + 35

2. Move all the terms to one side of the equation to set it equal to zero:

   18x^2 + 60x + 50 - 21x - 35 = 0

3. Combine like terms:

   18x^2 + 60x - 21x + 50 - 35 = 0

   This simplifies to:

   18x^2 + 39x + 15 = 0

4. Now, you need to factor this quadratic equation:

   The equation can be factored as follows:

   (3x + 5)(6x + 3) = 0

5. Set each factor equal to zero and solve for x:

   3x + 5 = 0 --> 3x = -5 --> x = -5/3

   6x + 3 = 0 --> 6x = -3 --> x = -3/6 --> x = -1/2

So, the solutions to the equation are x = -5/3 and x = -1/2.