Question

(x+3)(x-4) = -12help pls​

Answer 1

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Answer 2

(x+3)(x-4)= -12

x2-4x+3x-12= -12

x2-4x+3x=0

x2-x=0

x(x-1)=0

x=0

x-1=0

x=0

x=1

Answer 3

To solve the equation $(x+3)(x-4) = -12$, you can start by expanding the left side of the equation and then simplifying it:

$(x+3)(x-4) = -12$

Expanding the left side using the distributive property:

$x(x) + x(-4) + 3(x) + 3(-4) = -12$

Now, simplify each term:

$x^2 - 4x + 3x - 12 = -12$

Combine like terms:

$x^2 - x - 12 = -12$

Now, subtract $-12$ from both sides of the equation to isolate $x^2 - x$ on the left side:

$x^2 - x - 12 - (-12) = 0$

Simplify the equation:

$x^2 - x = 0$

Now, factor the left side of the equation:

$x(x - 1) = 0$

Now, set each factor equal to zero and solve for (x):

1. $x = 0$
2. $x - 1 = 0$

For the second equation, add 1 to both sides:

$x = 1$

So, there are two solutions to the equation:

$x = 0$ and $x = 1$.