Question

(x-4)*(x+3)=x^2+5x плиззззззззззззззз ​

Answer 1

Ответ:

$x = -2$

Объяснение:

$(x-4)(x+3) = x^2+5x\\\\x^2-4x+3x-12 = x^2+5x\\\\x^2-x^2-x-5x-12=0\\\\-6x-12=0\\\\6x=-12\\\\x=-2$

Answer 2

Sure, let's solve the equation:

(x - 4) * (x + 3) = x^2 + 5x

First, we'll use the distributive property to expand the left side of the equation:

(x - 4) * (x + 3) = x^2 - 4x + 3x - 12

Now, we can simplify the left side of the equation:

x^2 - 4x + 3x - 12 = x^2 - x - 12

So, the equation becomes:

x^2 - x - 12 = x^2 + 5x

Now, let's subtract x^2 from both sides of the equation to eliminate the x^2 terms:

(x^2 - x - 12) - (x^2 + 5x) = 0

Now, simplify:

x^2 - x - 12 - x^2 - 5x = 0

Now, combine like terms:

-6x - 12 = 0

To solve for x, we'll isolate x by adding 12 to both sides of the equation:

-6x = 12

Now, divide both sides by -6 to find the value of x:

x = 12 / -6 x = -2

So, the solution to the equation (x - 4) * (x + 3) = x^2 + 5x is:

x = -2