Question

(x- 1)(x+1)-x(x-3)=0

Answer 1

$(x-1)(x+1)-x(x-3)=0\\x^2-1-x^2+3x=0\\3x-1=0\\3x=1\\x=\frac{1}{3}$

Answer 2

To solve the equation $(x - 1)(x + 1) - x(x - 3) = 0$, you can follow these steps:

1. Expand the expressions on both sides of the equation:

   $(x - 1)(x + 1) - x(x - 3) = 0$

   $x(x + 1) - 1(x + 1) - x(x - 3) = 0$

2. Distribute the terms:

   $x^2 + x - x - 1 - x^2 + 3x = 0$

3. Simplify the equation by combining like terms:

   $x^2 - x - 1 - x^2 + 3x = 0$

   $-x + 3x - 1 = 0$

4. Combine the $x$ terms:

   $2x - 1 = 0$

5. Add 1 to both sides of the equation:

   $2x = 1$

6. Finally, divide both sides by 2 to solve for $x$:

   $x = \frac{1}{2}$

So, the solution to the equation is $x = \frac{1}{2}$.