Question

(3x+5)(2x+1)=(6x+5)( x-3)+7​

Answer 1

Ответ:

6x^2+3x+10x+5=6x^2-18x+5x-15+7

3x+10x+5=-18x+5x-15+7

13x+5=-13x-8

13x+13x=-8-5

26x=-13

x=-1/2

x=-0.5

Answer 2

To solve the equation (3x+5)(2x+1) = (6x+5)(x-3) + 7, follow these steps:

Step 1: Expand both sides of the equation using the distributive property.

On the left side: (3x+5)(2x+1) = 6x^2 + 3x + 10x + 5 = 6x^2 + 13x + 5

On the right side: (6x+5)(x-3) = 6x^2 - 18x + 5

So the equation becomes: 6x^2 + 13x + 5 = 6x^2 - 18x + 5 + 7

Step 2: Simplify the equation.

Now, subtract 6x^2 from both sides to cancel out the quadratic terms: 13x + 5 = -18x + 12

Step 3: Isolate x terms on one side and constants on the other side.

Add 18x to both sides: 13x + 18x + 5 = 12

Combine like terms: 31x + 5 = 12

Step 4: Subtract 5 from both sides to isolate the x terms: 31x = 12 - 5

Simplify the right side: 31x = 7

Step 5: Finally, divide both sides by 31 to solve for x: x = 7 / 31

So, the solution to the equation is: x = 7/31