Question

2(x+3)(x-2)-7=(2x+1)(x-3)​

Answer 1

Єто же легко

2(x+3)(x-2)-7=(2x+1)(x-3)=16/7

Answer 2

To solve the equation $2(x+3)(x-2)-7=(2x+1)(x-3)$, follow these steps:

1. Expand the expressions:

   $2(x+3)(x-2) - 7 = (2x+1)(x-3)$

   $2(x^2 - 2x + 3x - 6) - 7 = 2x^2 - 6x + x - 3x - 7$

   $2(x^2 + x - 6) - 7 = 2x^2 - 2x - 7$

   $2x^2 + 2x - 12 - 7 = 2x^2 - 2x - 7$

2. Simplify the equation:

   $2x^2 + 2x - 19 = 2x^2 - 2x - 7$

3. Subtract $2x^2$ from both sides to eliminate the quadratic terms:

   $2x - 19 = -2x - 7$

4. Add $2x$ to both sides:

   $4x - 19 = -7$

5. Add 19 to both sides:

   $4x = 12$

6. Divide by 4 to isolate $x$:

   $x = 3$

So, the solution to the equation is $x = 3$.