Question

2x3-50х = 0;9x² + 6x²+x=0​

Answer 1

Ответ:

Объяснение:

2х(х²-25)=0

2х=0.

х₁=0 ;

х²-25=0

х₁₂=±5.

15х²+х=0

х(15х+1)=0

х₁=0

15х+1=0

х₂=-1/15

Answer 2

Let's solve the two equations:

1. 2x^3 - 50x = 0:

First, factor out the common factor, which is 2x: 2x(x^2 - 25) = 0

Now, factor the quadratic expression inside the parentheses: 2x(x - 5)(x + 5) = 0

Now, set each factor equal to zero and solve for x: 2x = 0 => x = 0 x - 5 = 0 => x = 5 x + 5 = 0 => x = -5

So, the solutions to the first equation are x = 0, x = 5, and x = -5.

2. 9x^2 + 6x^2 + x = 0:

First, combine like terms on the left side: 15x^2 + x = 0

Now, factor out the common factor, which is x: x(15x + 1) = 0

Now, set each factor equal to zero and solve for x: x = 0 15x + 1 = 0

To solve for 15x + 1 = 0, subtract 1 from both sides: 15x = -1

Finally, divide both sides by 15 to isolate x: x = -1/15

So, the solutions to the second equation are x = 0 and x = -1/15.