Question

(y-4)(y-4)= (p-7)(7+p)=

Answer 1

Ответ:

1)у²-8у+16

2)р²-49

Объяснение:

Answer 2

Ответ:

1)у²-8у+16

2)р²-49

Объяснение:

Answer 3

To simplify the expression $(y-4)(y-4) = (p-7)(7+p)$, we can first expand both sides of the equation:

Expanding the left side: $(y-4)(y-4) = y^2 - 4y - 4y + 16$ $(y-4)(y-4) = y^2 - 8y + 16$

Expanding the right side: $(p-7)(7+p) = (p-7)(p+7)$ $(p-7)(7+p) = p(p) + p(7) - 7(p) - 7(7)$ $(p-7)(7+p) = p^2 + 7p - 7p - 49$

Now, we can simplify both sides of the equation:

On the left side, we have $y^2 - 8y + 16$.

On the right side, we have $p^2 - 49$.

So, the simplified equation is: $y^2 - 8y + 16 = p^2 - 49$

If you want to solve this equation for $y$ or $p$ or find a specific relationship between them, please provide additional information or context.