Question

16a (2 – a) + (4a – 5)^2 = 1

Answer 1

Ответ:

а1=(5-$\sqrt{14}$)/4

а2=(5+$\sqrt{14}$)/4

Объяснение:

Answer 2

16a (2 – a) + (4a – 5)^2 = 1
32a - 16a^2 + 16a^2 - 40a +25 - 1 = 0
32a - 40a +25 - 1 = 0
-8a + 24 = 0
8a = 24 <=> a = 24/8 = 3

Answer 3

To solve the equation 16a(2 - a) + (4a - 5)^2 = 1, follow these steps:

1. Expand the expressions on both sides of the equation:

   16a(2 - a) + (4a - 5)^2 = 1

   Expand the square: 16a(2 - a) + (4a - 5)(4a - 5) = 1

   Expand both expressions: 32a - 16a^2 + 16a^2 - 40a + 25 = 1

2. Now, simplify the equation:

   32a - 40a + 25 = 1

3. Combine like terms:

   -8a + 25 = 1

4. Subtract 25 from both sides of the equation to isolate the variable:

   -8a = 1 - 25

   -8a = -24

5. Finally, divide both sides by -8 to solve for 'a':

   a = (-24) / (-8)

   a = 3

So, the solution to the equation 16a(2 - a) + (4a - 5)^2 = 1 is a = 3.