Question

(x^2+3x)^2-x(5-x)(x+5)-5x(2x^3-5)=​

Answer 1

Объяснение:

-9x^4+7x^3+9x^2 это ответ

Answer 2

Let's simplify the given expression step by step:

$(x^2 + 3x)^2 - x(5 - x)(x + 5) - 5x(2x^3 - 5)$

First, expand $(x^2 + 3x)^2$:

$(x^2 + 3x)^2 = x^4 + 6x^3 + 9x^2$

Now, expand $x(5 - x)(x + 5)$:

$x(5 - x)(x + 5) = x(5x - x^2 + 5x) = x(10x - x^2) = 10x^2 - x^3$

And expand $5x(2x^3 - 5)$:

$5x(2x^3 - 5) = 10x^4 - 25x$

Now, let's put it all together:

$(x^2 + 3x)^2 - x(5 - x)(x + 5) - 5x(2x^3 - 5) = (x^4 + 6x^3 + 9x^2) - (10x^2 - x^3) - (10x^4 - 25x)$

Now, distribute the negative sign in the second and third terms:

$x^4 + 6x^3 + 9x^2 - 10x^2 + x^3 - 10x^4 + 25x$

Now, combine like terms:

$(x^4 - 10x^4) + (6x^3 + x^3) + (9x^2 - 10x^2) + 25x$

Simplify the exponents and coefficients:

$-9x^4 + 7x^3 - x^2 + 25x$

So, the simplified expression is $-9x^4 + 7x^3 - x^2 + 25x$.