Question

2) (3x +5)^2-5(5+3x)=0

Answer 1

Ответ:

Объяснение:

(3x +5)²-5(5+3x)=0

9x^2+30x+25-25-15x=0

9x^2+15x=0

3x(3x+5)=0

x1=0   ;  3x+5=0

             3x=-5

               x2=-5/3 = 1 2/3

Answer 2

To solve the equation (3x + 5)^2 - 5(5 + 3x) = 0, follow these steps:

1. Expand the terms on both sides of the equation:

   (3x + 5)^2 - 5(5 + 3x) = 0

   Expanding the left side:

   (3x + 5)(3x + 5) - 5(5 + 3x) = 0

   Now, apply the distributive property to both terms on the left side:

   (3x + 5)(3x) + (3x + 5)(5) - 5(5) - 5(3x) = 0

   9x^2 + 15x + 15x + 25 - 25 - 15x = 0

2. Simplify the equation:

   9x^2 + 30x = 0

3. Factor out the greatest common factor, which is 3x:

   3x(3x + 10) = 0

4. Set each factor equal to zero and solve for x:

   3x = 0 or 3x + 10 = 0

   For the first equation, divide both sides by 3:

   x = 0

   For the second equation, subtract 10 from both sides:

   3x = -10

   Divide both sides by 3:

   x = -10/3

So, the solutions to the equation are:

x = 0

x = -10/3