Question

1) 4x^=252) 3x^-8x=0​

Answer 1

^ – я так понимаю квадрат

Ответ:
1)
x₁ = 2,5
x₂ = -2,5

2)
x₁ = 0
x₂ = 8/3

Решение:
1)
4x² = 25
x² = 6,25
x₁ = √6,25 = 2,5
x₂ = -√6,25 = -2,5

2)
3x² - 8x = 0
x(3x - 8) = 0
x₁ = 0

3x - 8 = 0
3x = 8
x₂ = 8/3

Answer 2

It seems there might be some typographical errors in the equations you've provided. I'll try to correct them and provide solutions based on my assumptions:

1. If the first equation is supposed to be "4x^2 = 25," then the solution is as follows:

4x^2 = 25

First, divide both sides by 4 to isolate x^2:

x^2 = 25/4

Now, take the square root of both sides to solve for x:

x = ±√(25/4)

x = ±(5/2)

So, the solutions for this equation are x = 5/2 and x = -5/2.

2. If the second equation is supposed to be "3x^2 - 8x = 0," then the solution is as follows:

3x^2 - 8x = 0

Factor out the common term x:

x(3x - 8) = 0

Now, you have two factors to consider:

1. x = 0
2. 3x - 8 = 0

For the second factor:

3x - 8 = 0

Add 8 to both sides:

3x = 8

Divide both sides by 3:

x = 8/3

So, the solutions for this equation are x = 0 and x = 8/3.