Question

416. 1) -a²-2a-1;2) -9 +6b-b²:3) -2a² +8ab-8b²;4) -12ab-3a²- 12b²​

Answer 1

Ответ:

1) -a²-2a-1= -(a+1)²

2) -9 +6b-b²= -(b-3)²

3) -2a² +8ab-8b²= -2(a-2b)²

4) -12ab-3a²- 12b²= -3(a+2b)²

Объяснение:

вот так

Answer 2

Ответ:

Ответ будет 3 есле не правельно сооооооории

Объяснение:

Answer 3

It looks like you want to factor the following quadratic expressions:

1. -a² - 2a - 1
2. -9 + 6b - b²
3. -2a² + 8ab - 8b²
4. -12ab - 3a² - 12b²

Let's factor each of these expressions:

1. -a² - 2a - 1

This is a quadratic trinomial. To factor it, we look for two numbers that multiply to the constant term (-1) and add up to the coefficient of the linear term (-2). The numbers -1 and 1 meet these criteria:

-a² - 2a - 1 = (-a - 1)(a + 1)

So, the factored form is (-a - 1)(a + 1).

2. -9 + 6b - b²

This is also a quadratic trinomial. We can factor it by finding two numbers that multiply to the constant term (-9) and add up to the coefficient of the linear term (6). The numbers -3 and 3 meet these criteria:

-9 + 6b - b² = (3 - b)(3 + b)

So, the factored form is (3 - b)(3 + b).

3. -2a² + 8ab - 8b²

This expression is a quadratic trinomial. To factor it, we can use the distributive property to factor out a common factor of -2:

-2a² + 8ab - 8b² = -2(a² - 4ab + 4b²)

Now, we can factor the quadratic inside the parentheses:

a² - 4ab + 4b² = (a - 2b)(a - 2b)

So, the factored form is -2(a - 2b)(a - 2b).

4. -12ab - 3a² - 12b²

This is a quadratic trinomial. We can factor it by finding two numbers that multiply to the constant term (-12) and add up to the coefficient of the linear term (-3). The numbers 4 and -3 meet these criteria:

-12ab - 3a² - 12b² = (-3a + 4b)(4a + 3b)

So, the factored form is (-3a + 4b)(4a + 3b).

To summarize:

1. -a² - 2a - 1 = (-a - 1)(a + 1)
2. -9 + 6b - b² = (3 - b)(3 + b)
3. -2a² + 8ab - 8b² = -2(a - 2b)(a - 2b)
4. -12ab - 3a² - 12b² = (-3a + 4b)(4a + 3b)