Question

(3x-5)(2x+7)СРОЧНО....... ​

Answer 1

Відповідь:

(3x-5)(2x+7)

$(3x-5)*(2x+7)=6x^{2} +21x-10x-35=6x^{2} -11x-35$

Пояснення:

якщо треба далі розв'язувати, то через дискримінант

Answer 2

Looks like you're asking for the product of the expressions (3x-5) and (2x+7). To find this, you can use the FOIL method, which stands for First, Outer, Inner, Last.

So, let's multiply the terms:

First: $3x \times 2x = 6x^2$

Outer: $3x \times 7 = 21x$

Inner: $(-5) \times 2x = -10x$

Last: $(-5) \times 7 = -35$

Now, combine these results:

$6x^2 + 21x - 10x - 35$

Combine like terms:

$6x^2 + 11x - 35$

So, the product of (3x-5) and (2x+7) is $6x^2 + 11x - 35$.