Question

1.Найдите значение коэффициента b для графика функции у= 1,7х + b, если он проходит через точку с координатами (2;6); 2.Найдите координаты точки пересечения прямых 3х - у = 12 и 4х+у=2 Комментарий для 2: выразите переменную у из каждой формулы, приравняйте правые части полученных выражений, найдите х, решив уравнение, затем подставьте полученное число и найдите у)

Answer 1

Ответ:

$1)\ \ y=1,7x+b\\\\A(2;6)\ \ \to \ \ x=2\ , \y=6\\\\6=1,7\cdot 2+b\ \ ,\ \ 6=3,4+b\ \ ,\ \ \ b=6-3,4\ \ ,\ \ \ \boxed{b=2,6}\\\\\\2)\ \ 3x-y=12\ \ ,\ \ y=3x-12\\\\4x+y=2\ \ ,\ \ y=2-4x\\\\{}\ \ \ \ 3x-12=2-4x\ \ ,\ \ 3x+4x=2+12\ \ ,\ \ \ 7x=14\ \ ,\ \ \boxed{x=2}\\\\{}\ \ \ \ y=2-4x=2-4\cdot 2=2-8=-6\ \ ,\ \ \boxed{y=-6}\\\\tochka\ \ \boxed{\ M(2;-6)\ }$

Answer 2

The classification of your last message is [F].

For your first question, to find the value of the coefficient 'b' for the function y = 1.7x + b passing through the point (2, 6), you can use the provided point (2, 6) and plug it into the equation, solving for 'b'. Here's how:

6 = 1.7 * 2 + b

Now, you can solve for 'b':

6 = 3.4 + b

Subtract 3.4 from both sides:

b = 6 - 3.4 b = 2.6

So, the value of the coefficient 'b' is 2.6.

For your second question, to find the coordinates of the point of intersection of the lines 3x - y = 12 and 4x + y = 2, you can follow the steps you provided. First, express 'y' from both equations:

From 3x - y = 12, we can rearrange it to get:

y = 3x - 12

And from 4x + y = 2:

y = 2 - 4x

Now, you have two expressions for 'y':

1. y = 3x - 12
2. y = 2 - 4x

Set these two expressions equal to each other and solve for 'x':

3x - 12 = 2 - 4x

Add 4x to both sides:

7x - 12 = 2

Add 12 to both sides:

7x = 2 + 12 7x = 14

Now, divide by 7:

x = 14 / 7 x = 2

Now that you have the value of 'x,' you can substitute it back into either of the equations to find 'y.' Let's use the first equation:

y = 3x - 12 y = 3 * 2 - 12 y = 6 - 12 y = -6

So, the coordinates of the point of intersection are (2, -6).