Question

(у+8)^2=(5а+в)^2=(7с+3)(7с-3)=(2а-9в)(2а+9в)=​

Answer 1

1) (y + 8)² = y² + 2 * y * 8 + 8² = y² + 16y + 64

2) (5a + b)² = (5a)² + 2 * 5a * b + b² = 25a² + 10ab + b²

3) (7c + 3)(7c - 3) = (7c)² - 3² = 49c² - 9

4) (2a - 9b)(2a + 9b) = (2a)² - (9b)² = 4a² - 81b²

Answer 2

Ответ:

Объяснение:

Левлвле

Answer 3

The given equation is:

(у+8)^2 = (5а+в)^2 = (7с+3)(7с-3) = (2а-9в)(2а+9в)

Let's solve this step by step:

1. (у+8)^2 = (5а+в)^2 This equation tells us that the square of (у+8) is equal to the square of (5а+в). Take the square root of both sides to find the relationship between у, а, and в:

   у + 8 = 5а + в

2. (7с+3)(7с-3) This is a difference of squares, which can be factored as follows:

   (7с+3)(7с-3) = (7с)^2 - (3)^2 = 49с^2 - 9

3. (2а-9в)(2а+9в) This is also a difference of squares, which can be factored as follows:

   (2а-9в)(2а+9в) = (2а)^2 - (9в)^2 = 4а^2 - 81в^2

Now, we have the following equations:

1. у + 8 = 5а + в
2. 49с^2 - 9
3. 4а^2 - 81в^2

These equations represent relationships between у, а, в, and с based on the given expressions. However, to solve for specific values of these variables, you would need more information or additional equations. If you have more information or specific values for some of these variables, you can proceed to solve for the others.