Question

(x-7)^2+3=(x-2)(x+2)

Answer 1

(x-7)²+3=(x-2)(x+2)

-14x+49+3=-4

-14x+52=-4

-14x=-4-52

-14x=-56

x = -56/-14

x = 4

Answer 2

Ответ:

x²-14x+49+3=x²-4

-14x+49+3=-4

-14x+52=-4

-14x=-4-52

-14x=-56

x=4

Answer 3

To solve the equation $(x-7)^2 + 3 = (x-2)(x+2)$, you can follow these steps:

1. Expand both sides of the equation: $(x-7)(x-7) + 3 = (x-2)(x+2)$

2. Simplify the expressions: $x^2 - 14x + 49 + 3 = x^2 - 4$

3. Subtract $x^2$ from both sides to cancel out the $x^2$ terms: $-14x + 52 = -4$

4. Move the constant term (-4) to the left side by adding 4 to both sides: $-14x + 52 + 4 = 0$

5. Combine the constants on the left side: $-14x + 56 = 0$

6. Now, isolate the variable $x$ by dividing both sides by -14: $\frac{-14x + 56}{-14} = 0 / -14$

7. Simplify the left side: $x - 4 = 0$

8. Add 4 to both sides to solve for $x$: $x = 4$

So, the solution to the equation $(x-7)^2 + 3 = (x-2)(x+2)$ is (x = 4).