Question

(x²+1)² -10(x²+1) +25=0​

Answer 1

Ответ: х1=-2, х2=2

Объяснение:

$t^2-10t+25=0\\t=5\\x^{2} +1=5\\x1=-2. x2=2$

Answer 2

Ответ:

$t {}^{2} - 10t + 25 = 0$

$t = 5$

$x {}^{2} + 1 = 5$

$x = - 2$

$x = 2$

Объяснение:

если что , то уравнение имеет 2 решения

Answer 3

To solve the quadratic equation $(x^2 + 1)^2 - 10(x^2 + 1) + 25 = 0$, we can use a substitution. Let $y = x^2 + 1$. Now, the equation becomes:

$y^2 - 10y + 25 = 0$

This is a quadratic equation in $y$, and we can solve it by factoring:

$(y - 5)(y - 5) = 0$

Now, we have a repeated root at $y = 5$. To find the values of $x$, we need to substitute back for $y$:

$x^2 + 1 = 5$

Subtracting 1 from both sides:

$x^2 = 4$

Taking the square root of both sides:

$x = \pm 2$

So, the solutions for the equation $(x^2 + 1)^2 - 10(x^2 + 1) + 25 = 0$ are $x = 2$ and $x = -2$.