Question

X²-3x-4=!ТЕРМІНОВО!​

Answer 1

Ответ:

В объяснении.

Объяснение:

=х²+х-4х-4=х(х+1)-4(х+1)=(х+1)(х-4).

Answer 2

Объяснение:

Х^2-3х-4=х^2+х-4х-4=х(х+1)-4(х+1)=

=(х+1)(х-4)

Answer 3

To solve the quadratic equation $x^2 - 3x - 4 = 0$, you can use the quadratic formula, which is:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In this equation, $a = 1$, $b = -3$, and $c = -4$. Plug these values into the formula:

$x = \frac{-(-3) \pm \sqrt{(-3)^2 - 4(1)(-4)}}{2(1)}$

Now, calculate the discriminant ($b^2 - 4ac$):

$b^2 - 4ac = (-3)^2 - 4(1)(-4) = 9 + 16 = 25$

Now, you can solve for $x$:

$x = \frac{3 \pm \sqrt{25}}{2}$

Taking the square root of 25, we get two possible solutions:

1. $x = \frac{3 + 5}{2} = \frac{8}{2} = 4$
2. $x = \frac{3 - 5}{2} = \frac{-2}{2} = -1$

So, the solutions to the equation $x^2 - 3x - 4 = 0$ are $x = 4$ and $x = -1$.