Question

X^2+20x+100=0.......................................

Answer 1

Ответ:

-10

Объяснение:

х²+20х+100=0

Приведенное квадратное уравнение решаем по теореме Виета.

х1+х2=-20

х1*х2=100

х1=-10;   х2=-10

Уравнение имеет единственный корень х=-10.

Answer 2

Ответ:

x=-10

Объяснение:

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Answer 3

The equation you provided is a quadratic equation. To solve it, you can use the quadratic formula, which is given by:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In this equation, $a$, $b$, and $c$ represent the coefficients of the quadratic equation $ax^2 + bx + c = 0$.

In your equation, $a = 1$, $b = 20$, and $c = 100$. Substituting these values into the quadratic formula:

$x = \frac{-20 \pm \sqrt{20^2 - 4(1)(100)}}{2(1)}$

Simplify the equation:

$x = \frac{-20 \pm \sqrt{400 - 400}}{2}$

$x = \frac{-20 \pm \sqrt{0}}{2}$

Since the discriminant (the value inside the square root) is zero, there are no real solutions to this quadratic equation. In other words, the equation $x^2 + 20x + 100 = 0$ has no real roots. However, it does have complex roots. The roots are the same and are equal to:

$x = \frac{-20}{2} = -10$

So, the only solution for this equation is $x = -10$.