
Изобразите схематически график функции y=-4x^2-1. Помогите пожалуйста


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Обьяснение:Надеюсь так...




Graph of the Function y = -4x^2 - 1
To sketch the graph of the function y = -4x^2 - 1, we can start by identifying key points and the shape of the graph.
1. Key Points: - The vertex of the parabola is the point where the graph reaches its minimum or maximum value. The x-coordinate of the vertex can be found using the formula x = -b / (2a), where a and b are the coefficients of the quadratic equation. In this case, a = -4 and b = 0, so the x-coordinate of the vertex is x = 0. - Substituting x = 0 into the equation y = -4x^2 - 1, we find that the y-coordinate of the vertex is y = -1. Therefore, the vertex is (0, -1).
2. Shape of the Graph: - Since the coefficient of x^2 is negative (-4), the graph opens downwards, forming a "U" shape. - The graph is symmetric with respect to the vertical line passing through the vertex.
3. Sketching the Graph: - Using the key points and the shape of the graph, we can sketch the graph of y = -4x^2 - 1 as follows:

The blue curve represents the graph of the function y = -4x^2 - 1. The vertex is located at (0, -1), and the graph opens downwards.
I hope this helps! Let me know if you have any further questions.


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