Question

Два велосипедиста выехали одновременно навстречу друг другу из пункта А и Б встретились через 30 минут. Чему равно расстояние между А и Б если скорость одного велосипедиста v км/ч, а другого - на 2 км/ч меньше?

Answer 1

30 мин. = 0,5 ч

$v$ (км/ч) -   скорость первого велосипедиста

$v-2$ (км/ч)  -   скорость второго

$v+v-2=2v-2$  ( км/ч) -   скорость сближения велосипедистов

$(2v-2)*0,5=v-1$  (км)  -  расстояние между А и Б

Ответ:   $v-1$

Answer 2

Problem Analysis

We have two cyclists who start simultaneously from points A and B and meet after 30 minutes. The speed of one cyclist is v km/h, while the speed of the other cyclist is 2 km/h less than v. We need to find the distance between points A and B.

Solution

Let's assume the speed of the first cyclist is v km/h. Then the speed of the second cyclist is (v - 2) km/h.

We know that distance = speed × time. Since both cyclists meet after 30 minutes, the distance covered by the first cyclist is v × (30/60) = v/2 km, and the distance covered by the second cyclist is (v - 2) × (30/60) = (v - 2)/2 km.

The total distance between points A and B is the sum of the distances covered by both cyclists. Therefore, the distance between A and B is (v/2) + ((v - 2)/2) km.

Calculation

Let's calculate the distance between points A and B using the given information.

The distance between A and B is (v/2) + ((v - 2)/2) km.

Substituting the given values, we have:

Distance = (v/2) + ((v - 2)/2) km

Answer

The distance between points A and B is (v/2) + ((v - 2)/2) km.

Please note that the specific value of the distance cannot be determined without knowing the value of v.