Question

Помогите решить пж: разложить на множители. b^4+2b^2c+c^2= a^3-b^3c^3= x^3-6x^2+12x-8= x^3+9x+27x+27= a^2-b^2-a-b= a^3+a^2-a-1= 3ab+15b-3a-15= ПОМОГИТЕ РЕШИТЬ , СРОЧНО НУЖНО!!!!ПОЖАЛУЙСТА

Answer 1

Ответ:

на листочке, 5 не уверена

Объяснение:

Answer 2

Factoring Expressions

Let's break down the given expressions and solve them step by step.

1. b^4 + 2b^2c + c^2 To factor this expression, we can use the formula for factoring a perfect square trinomial: \(a^2 + 2ab + b^2 = (a + b)^2\). So, \(b^4 + 2b^2c + c^2 = (b^2 + c)^2\) [[1]].

2. a^3 - b^3c^3 This expression can be factored using the difference of cubes formula: \(a^3 - b^3 = (a - b)(a^2 + ab + b^2)\). Therefore, \(a^3 - b^3c^3 = (a - bc)(a^2 + abc + b^2c^2)\) [[2]].

3. x^3 - 6x^2 + 12x - 8 We can factor this expression by grouping: \(x^3 - 6x^2 + 12x - 8 = x^2(x - 6) + 4(3 - 2x) = (x - 2)(x - 2)^2\) [[3]].

4. x^3 + 9x + 27x + 27 This expression can be factored by grouping as well: \(x^3 + 9x + 27x + 27 = x(x^2 + 9) + 27(x + 1) = (x + 3)(x^2 - 3x + 9)\) [[4]].

5. a^2 - b^2 - a - b We can factor this expression using the difference of squares formula: \(a^2 - b^2 = (a - b)(a + b)\). So, \(a^2 - b^2 - a - b = (a - b)(a + b) - (a + b) = (a - b - 1)(a + b)\) [[5]].

6. a^3 + a^2 - a - 1 This expression can be factored by grouping: \(a^3 + a^2 - a - 1 = a^2(a + 1) - 1(a + 1) = (a^2 - 1)(a + 1) = (a - 1)(a + 1)(a + 1)\) [[6]].

7. 3ab + 15b - 3a - 15 We can factor this expression by grouping: \(3ab + 15b - 3a - 15 = 3b(a + 5) - 3(a + 5) = (3b - 3)(a + 5) = 3(b - 1)(a + 5)\) [[7]].

I hope this helps you with your urgent need! Let me know if you need further assistance with anything else.