Question

1)(2-х)(2+х)+х^2(х-1)2)(х-5)^2-4(х+5)^23)(х^2+2)^2-4(х^2+2)+4помогите пожалуйста)))​

Answer 1

Ответ:

Объяснение:

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Answer 2

Task 1: Simplifying the Expression

To simplify the given expression, let's expand and combine like terms:

1) (2-х)(2+х)+х^2(х-1): Expanding the first part of the expression using the FOIL method, we get: (2 - x)(2 + x) = 2 * 2 + 2 * x - 2 * x - x^2 = 4 + 2x - 2x - x^2 = 4 - x^2

Expanding the second part of the expression, we get: x^2(х - 1) = x^2 * x - x^2 * 1 = x^3 - x^2

Combining the two parts, we have: (2 - x)(2 + x) + x^2(х - 1) = 4 - x^2 + x^3 - x^2 = x^3 - 2x^2 + 4

2) (х-5)^2-4(х+5)^2: Expanding the first part of the expression using the square of a binomial formula, we get: (х - 5)^2 = х^2 - 2 * х * 5 + 5^2 = х^2 - 10х + 25

Expanding the second part of the expression using the square of a binomial formula, we get: (х + 5)^2 = х^2 + 2 * х * 5 + 5^2 = х^2 + 10х + 25

Substituting the expanded forms into the expression, we have: (х - 5)^2 - 4(х + 5)^2 = (х^2 - 10х + 25) - 4(х^2 + 10х + 25) = х^2 - 10х + 25 - 4х^2 - 40х - 100 = -3х^2 - 50х - 75

3) (х^2+2)^2-4(х^2+2)+4: Expanding the first part of the expression using the square of a binomial formula, we get: (х^2 + 2)^2 = х^4 + 2 * х^2 * 2 + 2^2 = х^4 + 4х^2 + 4

Expanding the second part of the expression, we get: -4(х^2 + 2) = -4х^2 - 8

Substituting the expanded forms into the expression, we have: (х^2 + 2)^2 - 4(х^2 + 2) + 4 = (х^4 + 4х^2 + 4) - 4х^2 - 8 + 4 = х^4 + 4 - 4х^2 - 4х^2 - 4 = х^4 - 8х^2

Therefore, the simplified expressions are: 1) x^3 - 2x^2 + 4 2) -3x^2 - 50x - 75 3) x^4 - 8x^2

Let me know if you need any further assistance!