Question

X³-y³= a³b³-c³=a³+8=​

Answer 1

Ответ:

$x ^{3} - y {}^{3 } = (x - y) \times (x { }^{2} + xy + y {}^{2} )$

$a {}^{3} b {}^{3} - c {}^{3} = (ab - c) \times (a {}^{2} b {}^{2} + abc + c {}^{2} )$

$a {}^{3} + 8 = (a + 2) \times (a {}^{2} - 2a + 4)$

Answer 2

1) x³-y³=(x-y)(x²+y²+xy)

2) a³b³-c³=(ab-c)(a²b²+c²+abc)

3) a³+8=(a+2)(a²+4-2a)

Answer 3

I can help you with math problems.

To answer your question, I will use the difference of cubes formula:

$$a^3 - b^3 = (a - b)(a^2 + ab + b^2)$$

Let $a = x$ and $b = y$. Then we have:

$$x^3 - y^3 = (x - y)(x^2 + xy + y^2)$$

Now, let $a^3 b^3 - c^3 = a^3 + 8$. Then we can factor it as:

$$(ab - c)(a^2 b^2 + abc + c^2) = a^3 + 8$$

To solve for $x$ and $y$, we need to equate the two expressions and find the common factors. One possible solution is:

$$x - y = ab - c$$ $$x^2 + xy + y^2 = a^2 b^2 + abc + c^2$$

If we let $a = 2$, $b = 1$, and $c = 1$, then we get:

$$x - y = 1$$ $$x^2 + xy + y^2 = 6$$

Solving this system of equations gives us:

$$x = \frac{3 + \sqrt{5}}{2}$$ $$y = \frac{3 - \sqrt{5}}{2}$$

You can check your answer using a math solver tool or a factoring calculator or .

I hope this helps. If you have any other questions, feel free to ask me.

: https://www.geogebra.org/solver : https://www.mathway.com/popular-problems/Algebra/246936 : https://www.mathway.com/Calculator/factoring-calculator