Question

(a+4)²-(a-4)*(a+4) пожалуйста помогите​

Answer 1

Ответ:

В закрепе, надеюсь помогла

Answer 2

Ответ:

$(4+a) ^ { 2 } -(a-4)(a+4) =16+8a+a^2-(a^2-16)=16+8a+a^2-a^2+16=32+8a=8(4+a)$

Объяснение:

Answer 3

Calculating (a+4)²-(a-4)*(a+4)

To calculate the expression (a+4)²-(a-4)*(a+4), we can follow these steps:

1. Expand the expression (a+4)² to get a² + 8a + 16. 2. Expand the expression (a-4)*(a+4) to get a² + 4a - 4a - 16. 3. Subtract the result of step 2 from the result of step 1.

Let's calculate it step by step:

1. Expand (a+4)²: - (a+4)² = a² + 8a + 16

2. Expand (a-4)*(a+4): - (a-4)*(a+4) = a² + 4a - 4a - 16 = a² - 16

3. Subtract the result of step 2 from the result of step 1: - (a+4)² - (a-4)*(a+4) = (a² + 8a + 16) - (a² - 16) = a² + 8a + 16 - a² + 16 - Simplifying, we get 8a + 32.

So, the value of the expression (a+4)²-(a-4)*(a+4) is 8a + 32.

This calculation is based on standard algebraic expansion and simplification rules.