Question

(2x-1)(2x+1)=(x+3)²+x(3x-1)

Answer 1

Ответ:

Объяснение:

(2x-1)(2x+1)=(x+3)^2+x (3x-1)

4x^2-1=x^2+6x+9+3x^2-x

4x^2-x^2-3x^2-6x+x=9+1

-5x=10

5x= -10

x= -10/5

x= -2

Answer 2

Let's solve the given equation step by step:

Expanding the left side of the equation: (2x - 1)(2x + 1) = (2x)² - 1² = 4x² - 1

Expanding the right side of the equation: (x + 3)² + x(3x - 1) = (x + 3)(x + 3) + x(3x - 1) = x² + 6x + 9 + 3x² - x = 4x² + 5x + 9

Now we have the equation: 4x² - 1 = 4x² + 5x + 9

Subtracting 4x² from both sides: -1 = 5x + 9

Subtracting 9 from both sides: -10 = 5x

Dividing by 5: x = -10/5 x = -2

Therefore, the solution to the equation (2x - 1)(2x + 1) = (x + 3)² + x(3x - 1) is x = -2.