Question

СРОЧНО ПОЖАЛУЙСТА! Найди с помощью подбора корни уравнения x^2-10x+16=0

Answer 1

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Answer 2

Ответ:

8; 2

Объяснение:

• Теорема Виета: Произведение корней уравнения x²+px+q=0, равно свободному члену "q", а сумма корней равна коэффициенту "р" с противоположным знаком. Корни ищем методом подбора.

$x {}^{2} - 10x + 16 = 0.$

Сумма корней = 10.

Произведение = 16.

Корни = 8 и 2.

Ведь 8·2=16 и 8+2=10.

Answer 3

Solving the Quadratic Equation x^2 - 10x + 16 = 0

To find the roots of the quadratic equation x^2 - 10x + 16 = 0, we can use the quadratic formula:

Quadratic Formula: For a quadratic equation of the form ax^2 + bx + c = 0, the solutions for x are given by: x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, the coefficients are: a = 1, b = -10, and c = 16.

Using the Quadratic Formula: Substituting the values of a, b, and c into the quadratic formula, we get: x = (-(-10) ± √((-10)^2 - 4*1*16)) / (2*1) = (10 ± √(100 - 64)) / 2 = (10 ± √36) / 2 = (10 ± 6) / 2

So, the roots of the equation x^2 - 10x + 16 = 0 are: x1 = (10 + 6) / 2 = 16 / 2 = 8 x2 = (10 - 6) / 2 = 4 / 2 = 2

Therefore, the roots of the given equation are x = 8 and x = 2.