Question

(4y-3m)^2+(3m-5y)(3m+5y)+24my

Answer 1

Ответ:

-9y²-24my+18m²+24m

Объяснение:

(4y-3m)²+(3m-5y)(3m+5y)+24my=

=16y²-24my+9m²+9m²-25y²+24=

=-9y²-24my+18m²+24m

Answer 2

To simplify the expression, let's expand and combine like terms:

(4y - 3m)^2 + (3m - 5y)(3m + 5y) + 24my

Expanding the first term using the square of a binomial formula: (4y - 3m)^2 = (4y)^2 - 2(4y)(3m) + (3m)^2 = 16y^2 - 24ym + 9m^2

Expanding the second term using the difference of squares formula: (3m - 5y)(3m + 5y) = (3m)^2 - (5y)^2 = 9m^2 - 25y^2

Now let's simplify the expression further by combining like terms:

(16y^2 - 24ym + 9m^2) + (9m^2 - 25y^2) + 24my

Combining like terms: 16y^2 - 24ym + 9m^2 + 9m^2 - 25y^2 + 24my

Simplifying: 16y^2 - 25y^2 - 24ym + 24my + 9m^2 + 9m^2

Combining like terms: -9y^2 + 0ym + 18m^2

Simplifying further, we get the final expression: -9y^2 + 18m^2