Question

B¯¹⁴ * (4b в восьмой степени)²

Answer 1

$\displaystyle\bf\\b^{-14} \cdot\bigg(4b^{8} \bigg)^{2} =b^{-14} \cdot16b^{16} =16\cdotb^{-14+16} =16b^{2}$

Answer 2

Ответ:

$16b^{2}$

Объяснение:

$b^{-14} \cdot (4b^{8})^{2}=b^{-14} \cdot 4^{2} \cdot (b^{8})^{2}=b^{-14} \cdot 16 \cdot b^{8 \cdot 2}=16 \cdot b^{-14} \cdot b^{16}=16 \cdot b^{-14+16}=$

$=16 \cdot b^{16-14}=16 \cdot b^{2}=16b^{2};$

Answer 3

To simplify the expression B¯¹⁴ * (4b в восьмой степени)², let's break it down step by step:

First, let's clarify the notation used in the expression:

• B¯¹⁴ represents the reciprocal of B raised to the power of 14.
• (4b в восьмой степени)² represents the expression (4b raised to the power of 8) squared.

Now let's simplify it:

1. Start with (4b в восьмой степени)²: (4b)⁸ ² = (4²)⁸ (b⁸)² = 16⁸ b¹⁶ = 65,536 b¹⁶

2. Multiply the above result by B¯¹⁴: B¯¹⁴ * 65,536 b¹⁶ = (1 / B¹⁴) * 65,536 b¹⁶ = 65,536 b¹⁶ / B¹⁴

So the simplified expression is 65,536 b¹⁶ / B¹⁴.