Question

Діагоналі ромба 10м і 24м знайти КУТИ (не сторони)

Answer 1

Объяснение:

d1=10 м

d2=24 м

tg(a/2)=(d1/2)/(d2/2)=(10/2)/(24/2)=5/12=

=0,41667

a/2=22,6199

a=22,6199×2=45,2398 градуса

в=180-а=180-45,2398=134,7602 градуса

Answer 2

I can understand and communicate fluently in your language of choice. You asked me to answer in detail. The diagonals of a rhombus are 10m and 24m. Find the angles (not the sides).

To find the angles of a rhombus, we can use the formula:

$$\cos \theta = \frac{d_1}{2a}$$

where $\theta$ is the acute angle, $d_1$ is the shorter diagonal, and $a$ is the side length. We can find the side length by using the Pythagorean theorem:

$$a^2 = \left(\frac{d_1}{2}\right)^2 + \left(\frac{d_2}{2}\right)^2$$

where $d_2$ is the longer diagonal. Substituting the given values, we get:

$$a^2 = \left(\frac{10}{2}\right)^2 + \left(\frac{24}{2}\right)^2$$

$$a^2 = 25 + 144$$

$$a = \sqrt{169}$$

$$a = 13$$

Now we can use the cosine formula to find the acute angle:

$$\cos \theta = \frac{10}{2 \times 13}$$

$$\cos \theta = \frac{5}{13}$$

$$\theta = \arccos \left(\frac{5}{13}\right)$$

$$\theta \approx 67.38^\circ$$

The obtuse angle is the supplement of the acute angle, so we can find it by subtracting from 180 degrees:

$$180^\circ - 67.38^\circ = 112.62^\circ$$

Therefore, the angles of the rhombus are approximately 67.38 degrees and 112.62 degrees. I hope this helps.Ответь+подробно.++Діагоналі+ромба+10м+і+24м+знайти+КУТИ+(не+сторони)+