Question

У прямокутному трикутнику АВС , АС=b, кут В дорівнює -бета. Знайдіть: кут А, сторони: АВ, ВС.срочно дам 40 балов

Answer 1

Ответ:

Объяснение:

   ΔАВС - прямокутний ; ∠С = 90° .

   ∠А = 90° - ∠В = 90° - β ;     ∠А = 90° - β .

   sinβ = AC/AB ;    AB = AC/sinβ = b/sinβ ;    AB = b/sinβ .

    ctgβ = BC/AC ;   BC = AC *ctgβ = b*ctgβ ; BC = b*ctgβ .

Answer 2

Finding the Angle A, Sides AB, and BC in a Right-Angled Triangle

To find the angle A and the sides AB and BC in a right-angled triangle ABC, where AC = b and angle B is equal to -beta, we can use trigonometric functions.

Let's start by finding the angle A. In a right-angled triangle, the sum of all angles is 180 degrees. Since angle B is given as -beta, we can use the fact that the sum of the angles in a triangle is 180 degrees to find angle A.

Using the formula for the sum of angles in a triangle: Angle A = 90 degrees + beta.

Next, let's find the sides AB and BC. Since we know that AC = b, we can use trigonometric functions to find the other sides.

Using the trigonometric ratios in a right-angled triangle: AB = AC * cos(A), BC = AC * sin(A).

Substituting the values: AB = b * cos(90 degrees + beta), BC = b * sin(90 degrees + beta).

Now, we can calculate the values of AB and BC using the given information.

I hope this helps! If you have any further questions or need additional assistance, feel free to ask.