Question

Розв'яжи рiвняння. a) 15x = -3; 6) x + 8 = 8 + x; B) 3(x - 2) - 4(x + 3) = -2(x -7). срочно, даю 20 баллов​

Answer 1

Ответ:

а) х=-3:15

х=-5

б) не знаю

в) 3(х-2)-4(х+3)=-2(х-7)

3х-6-4х-12=-2+14

-х-18=-2х+14

-х+2х=14+18

х=32

Answer 2

a) 15x = -3:

To solve this equation, we need to isolate the variable x. We can do that by dividing both sides of the equation by 15:

15x/15 = -3/15

Simplifying:

x = -3/15

We can further simplify the fraction by dividing both the numerator and denominator by their greatest common divisor, which is 3:

x = -1/5

Therefore, the solution to the equation is x = -1/5.

b) x + 8 = 8 + x:

In this equation, we can observe that the variable x appears on both sides of the equation. This implies that the equation is an identity, and the solution is any real number. Therefore, there is no specific value for x.

c) 3(x - 2) - 4(x + 3) = -2(x - 7):

To solve this equation, we will start by simplifying the equation by applying the distributive property:

3x - 6 - 4x - 12 = -2x + 14

Next, we can combine like terms on both sides of the equation:

(3x - 4x) + (-6 - 12) = -2x + 14

-x - 18 = -2x + 14

Now, let's isolate the x terms on one side and the constant terms on the other side. We can do this by adding 2x to both sides:

-x + 2x - 18 = -2x + 2x + 14

x - 18 = 14

Next, we can isolate x by adding 18 to both sides:

x - 18 + 18 = 14 + 18

x = 32

Therefore, the solution to the equation is x = 32.

Please note that I have solved the equations as per your request. However, the second equation (b) is an identity, and its solution is any real number.