Question

(x-4)(y+3)(m-2)(n-y)​

Answer 1

Объяснение:

(x-4)(y+3)=ху-4у+3х-12

(m-2)(n-y)​=mn-2n-my+2y

Answer 2

To expand the expression (x-4)(y+3)(m-2)(n-y), we can use the distributive property multiple times. Let's break it down step by step:

Step 1: Expand (x-4) and (y+3): (x-4)(y+3) = xy + 3x - 4y - 12

Step 2: Expand (m-2) and (n-y): (m-2)(n-y) = mn - my - 2n + 2y

Now, we have: (xy + 3x - 4y - 12)(mn - my - 2n + 2y)

Step 3: Expand the remaining terms: = xy * mn + xy * (-my) + xy * (-2n) + xy * (2y) + 3x * mn + 3x * (-my) + 3x * (-2n) + 3x * (2y) + (-4y) * mn + (-4y) * (-my) + (-4y) * (-2n) + (-4y) * (2y) + (-12) * mn + (-12) * (-my) + (-12) * (-2n) + (-12) * (2y)

Simplifying each term gives us: = xymn - xym^2 - 2xyn + 2xy^2 + 3xmn - 3xym - 6xn + 6xy + -4ymn + 4ym^2 + 8yn - 8y^2 + -12mn + 12my + 24n - 24y

Finally, we can combine like terms to get the expanded expression: xymn - xym^2 - 2xyn + 2xy^2 + 3xmn - 3xym - 6xn + 6xy + -4ymn + 4ym^2 + 8yn - 8y^2 + -12mn + 12my + 24n - 24y