Question

(4x-3)(4x+3)−(4x-1)²-3x = 0 ​

Answer 1

(4х-3)(4х+3)-(4х-1)²=3х

16х²-9-16х²+8х-1-3х=0

5х-10=0

х=2

Answer 2

Let's solve the given equation step by step:

(4x-3)(4x+3) - (4x-1)² - 3x = 0

Expanding the products, we have:

(16x² - 9) - (16x² - 8x + 1) - 3x = 0

Removing the parentheses and simplifying, we get:

16x² - 9 - 16x² + 8x - 1 - 3x = 0

Combining like terms, we have:

16x² - 16x² + 8x - 3x - 9 - 1 = 0

5x - 10 = 0

Adding 10 to both sides, we get:

5x = 10

Dividing both sides by 5, we obtain the solution:

x = 2

Therefore, the value of x that satisfies the equation is x = 2.