Question

(3y-2)(y+4)-3(y+3)(y-1)=0

Answer 1

Ответ:

y=−17|8

Объяснение:

........... .........

Answer 2

Let's solve the given equation:

(3y - 2)(y + 4) - 3(y + 3)(y - 1) = 0

Expanding the equation, we get:

(3y^2 + 12y - 2y - 8) - (3y^2 - 3y + 9y - 9) = 0

Simplifying further, we combine like terms:

3y^2 + 12y - 2y - 8 - 3y^2 + 3y - 9y + 9 = 0

3y^2 and -3y^2 cancel out, and 12y - 2y + 3y - 9y combine to give 4y:

4y - 8 + 9 = 0

Combining constants, we get:

4y + 1 = 0

Subtracting 1 from both sides, we have:

4y = -1

Finally, dividing both sides by 4, we find the solution for y:

y = -1/4

Therefore, the solution to the given equation is y = -1/4.