Question

У= x²+ x - 4 y =6 - x²

Answer 1

1) y=x+х-4

a=1,b=1

X=-1/2•1

Х=-1/2

y=x^2+x-4, х=-1/2
Ответ: (-1/2; -17/4)

2) y=6-x^2

y=-x^2+6

a=-1, b=0

Х=-0,2•(-1)

Х=0

y=6-x^2, х=0
Ответ: (0;6)

Answer 2

To solve the system of equations given by:

Equation 1: U = x² + x - 4 Equation 2: y = 6 - x²

We can substitute the expression for y from Equation 2 into Equation 1 and solve for x. Let's do that:

U = x² + x - 4 y = 6 - x²

Substituting y into U: U = x² + x - 4 U = 6 - x² + x - 4 U = -x² + x + 2

Now we have a single equation in terms of U and x. To find the values of x and U, we can either graph the equation or solve it algebraically.

If you're looking for specific values, please let me know, and I can help you further.