Question

Розкладіть на множники: 1) 4a²-0,49; 2) м² -18m + 81; 3) c3 +64; г)5-5a².​срочно, пожалуйста!!

Answer 1

Ответ:

ответ готов

Объяснение:

Answer 2

1. 4a² - 0.49: To factorize this expression, we can recognize it as the difference of squares. The square root of 4a² is 2a, and the square root of 0.49 is 0.7. Thus, we have:

4a² - 0.49 = (2a - 0.7)(2a + 0.7)

2. m² - 18m + 81: To factorize this quadratic expression, we can use the perfect square trinomial form. The square root of m² is m, the square root of 81 is 9, and twice the product of the square roots is -18m. Therefore, we have:

m² - 18m + 81 = (m - 9)(m - 9) = (m - 9)²

3. c³ + 64: To factorize this expression, we can use the sum of cubes formula. The cube root of c³ is c, and the cube root of 64 is 4. Thus, we have:

c³ + 64 = (c + 4)(c² - 4c + 16)

г) 5 - 5a²: To factorize this expression, we can factor out a common factor of 5 from both terms. We get:

5 - 5a² = 5(1 - a²)

Now, we can further factor the difference of squares:

5(1 - a²) = 5(1 - a)(1 + a)

Therefore, the factored form of the expression is 5(1 - a)(1 + a).