Question

3a×(3a−a^(2))−4a×(2a^(2)−5a)

Answer 1

Ответ:

$29a^{2}-11a^{3}$

Объяснение:

$3a(3a-a^{2})-4a(2a^{2}-5a)=3a \cdot 3a-3a \cdot a^{2}-4a \cdot 2a^{2}-4a \cdot (-5a)=9a^{2}-$

$-3a^{3}-8a^{3}+20a^{2}=29a^{2}-11a^{3};$

Answer 2

To simplify the expression 3a × (3a - a^2) - 4a × (2a^2 - 5a), let's break it down step by step:

First, simplify the expressions within each set of parentheses:

3a × (3a - a^2) can be expanded as follows: = 3a × 3a - 3a × a^2 = 9a^2 - 3a^3

Similarly, 4a × (2a^2 - 5a) can be expanded as: = 4a × 2a^2 - 4a × 5a = 8a^3 - 20a^2

Now, substitute the simplified expressions back into the original expression:

3a × (3a - a^2) - 4a × (2a^2 - 5a) = (9a^2 - 3a^3) - (8a^3 - 20a^2)

Next, distribute the negative sign through the second set of parentheses:

= 9a^2 - 3a^3 - 8a^3 + 20a^2

Now, combine like terms:

= (9a^2 + 20a^2) + (-3a^3 - 8a^3) = 29a^2 - 11a^3

Therefore, the simplified expression is 29a^2 - 11a^3.