Question

Решить неравенство: 1)5(х+2) + 2(х-3)<3(x-1)+4x 2)3(2x-1)+ 3(x-1)>5(x+2)+2(2x-3)

Answer 1

6x-3+3x-3>5x+10+4x-6
9x-6>9x=4
9x-9x-6-4>0
-10>0

Answer 2

Let's begin by simplifying each side of the inequality:

5(x+2) + 2(x-3) < 3(x-1) + 4x

5x + 10 + 2x - 6 < 3x - 3 + 4x

7x + 4 < 7x - 3

We can see that the variable "x" has cancelled out, leaving us with the statement "7 < -3", which is false. Therefore, there are no values of "x" that make the inequality true, and the solution set is empty.

Again, let's simplify each side of the inequality:

3(2x-1) + 3(x-1) > 5(x+2) + 2(2x-3)

6x - 3 + 3x - 3 > 5x + 10 + 4x - 6

9x - 6 > 9x + 4

We can see that the variable "x" has cancelled out again, leaving us with the statement "-6 > 4", which is false. Therefore, there are no values of "x" that make the inequality true, and the solution set is empty.