Question

(1-)(1++x)

Answer 1

(1-√х)(1+√х + х)=(1-√х)(1+√х)+х(1-√х)=[применим формулу разности квадратов а²-b²-(a-b)(a+b)]= 1-х+х-х√х=1-х√х

Answer 2

To simplify this expression, we can use the following steps:

1. Distribute the negative sign to both terms inside the parentheses:

(1 - 1) - x

2. Simplify the expression inside the parentheses:

0 - x

3. Simplify the final expression:

-x

Therefore, (1-)(1++x) simplifies to -x.