Question

X^2-7x+4=0 ?????????

Answer 1

D=B^2-4AC

D = 49-4*4*1

D = 49 - 16 = 33

√D = √33

x = (7±√3)/2

x1 = (7+√3)/2

x2 = (7-√3)/2

Answer 2

To solve the quadratic equation X^2 - 7x + 4 = 0, you can use the quadratic formula:

X = (-b ± sqrt(b^2 - 4ac)) / 2a

where a, b, and c are the coefficients of the equation in standard form (ax^2 + bx + c = 0).

In this case, a = 1, b = -7, and c = 4. Substituting these values into the quadratic formula, we get:

X = (-(-7) ± sqrt((-7)^2 - 4(1)(4))) / 2(1) X = (7 ± sqrt(49 - 16)) / 2 X = (7 ± sqrt(33)) / 2

So the solutions to the equation X^2 - 7x + 4 = 0 are:

X = (7 + sqrt(33)) / 2 or X = (7 - sqrt(33)) / 2