Question

Вычислите:a)(√3+2√2)²-4√6;

Answer 1

$( \sqrt{3} + 2 \sqrt{2} ) {}^{2} - 4 \sqrt{6} = 3 + 4 \sqrt{6} + 8 - 4 \sqrt{6} = 3 + 8 = 11$

Answer 2

$3 + 4 \sqrt{6 } + 8 - 4 \sqrt{6} =3+8= 11$

Ответ:11

Answer 3

Let's begin by expanding the square of (√3+2√2):

(√3+2√2)² = (√3)² + 2(√3)(2√2) + (2√2)² = 3 + 4√6 + 8

Simplifying, we have:

(√3+2√2)² = 11 + 4√6

Now, we can substitute this expression into the original equation and simplify:

(√3+2√2)² - 4√6 = (11 + 4√6) - 4√6 = 11

Therefore, the value of the expression is 11.