Question

Решите уравнения : 1) 2x+3/3 + 4x-3/3 = 1; 2)2x+1/5 + 3x+1/7 = 2;

Answer 1

1)на 3
2x+3+4x-3=3
6x=3
x=0,5

2)домножим на 35 и получим

7(2x+1)+5(3x+1)=2

14x+7 +15x+5 =70

29x=58

x=2

Answer 2

We can start by simplifying the left-hand side of the equation by finding a common denominator for the two fractions:

2x + 3/3 + 4x - 3/3 = 1 2x + 4x = 1 - 3/3 - 3/3 6x = 1 - 2/3 6x = 1/3 x = 1/18

Therefore, the solution to the equation is x = 1/18.

Again, we can start by finding a common denominator for the two fractions on the left-hand side of the equation:

2x + 1/5 + 3x + 1/7 = 2 (2x * 7 + 1 * 7 + 3x * 5 + 1 * 5) / (5 * 7) = 2 (14x + 7 + 15x + 5) / 35 = 2 29x + 12 = 70 29x = 58 x = 2

Therefore, the solution to the equation is x = 2.